Which Way Do Option Prices Move? Six Inputs, Four Options

Options Pricing · Easy · Free problem

Consider plain vanilla European and American calls and puts on a stock. For each of the following inputs, explain how the price of each of the four options changes when that input increases while everything else is held fixed:

(a) the current stock price $S$;

(b) the strike price $K$;

(c) the time to maturity $T$;

(d) the volatility $\sigma$;

(e) the risk-free interest rate $r$;

(f) the dividends paid by the stock before expiry.

Give a one-line economic reason for each direction, and point out any case where the direction is *not* determined without further assumptions.

Hints

  1. Fix everything except one input and ask what happens to the payoff $(S_T - K)^+$ or $(K - S_T)^+$, or to the present value of the strike, when that input moves.
  2. For time to maturity, separate the American case (a longer-dated option contains a shorter-dated one, so it can never be worth less) from the European case (you cannot exercise early, so a longer wait can hurt).
  3. For the European exceptions, think of a deep in-the-money put: it is roughly worth $Ke^{-rT} - S$, and $Ke^{-rT}$ falls as $T$ grows. Similarly, a European call on a high-dividend stock loses the dividends paid before expiry.

Worked Solution

How to Think About It: Change one input at a time and ask two questions: does the change make the payoff at expiry larger, and does it change what the payoff is worth today (discounting, or the risk-neutral drift of the stock)? For American options add a third question: does the change give the holder more choices? A longer-dated American option always contains the shorter-dated one, so extra time can never hurt. A European holder has no such protection, and that is where the only ambiguous sign lives.

Quick Estimate: Under Black-Scholes-Merton with continuous dividend yield $y$, $$c = S e^{-yT} N(d_1) - K e^{-rT} N(d_2), \qquad p = K e^{-rT} N(-d_2) - S e^{-yT} N(-d_1),$$ and the signs of the partial derivatives are: $\partial c/\partial S = e^{-yT}N(d_1) > 0$, $\partial p/\partial S = -e^{-yT}N(-d_1) < 0$; $\partial c/\partial K < 0 < \partial p/\partial K$; $\partial c/\partial \sigma = \partial p/\partial \sigma = S e^{-yT}\sqrt{T}\,N'(d_1) > 0$; $\partial c/\partial r = TKe^{-rT}N(d_2) > 0$, $\partial p/\partial r = -TKe^{-rT}N(-d_2) < 0$; $\partial c/\partial y < 0 < \partial p/\partial y$. Only $\partial/\partial T$ has no fixed sign for European options.

Formal Solution:

*Step 1 -- Stock price $S$ increases.* The call payoff $(S_T - K)^+$ is nondecreasing in $S_T$ and the put payoff $(K - S_T)^+$ is nonincreasing, and a higher $S$ today shifts the whole distribution of $S_T$ upward. So calls (European and American) rise and puts fall.

*Step 2 -- Strike $K$ increases.* A higher strike lowers every call payoff and raises every put payoff, and it also raises the present value of what a put holder receives. Calls fall, puts rise, for both exercise styles.

*Step 3 -- Time to maturity $T$ increases.* American: a $T_2$-option ($T_2 > T_1$) can be exercised at any time up to $T_1$ as well, so it is worth at least as much. Both American calls and puts rise (weakly). European: extra time raises the dispersion of $S_T$ (good for both) but also changes the present value of the strike and the dividends lost. For a European call on a non-dividend stock, early exercise is never optimal, so the European and American calls coincide and the value rises with $T$. For a European put, longer maturity lowers $Ke^{-rT}$, which is what the holder ultimately receives; a deep in-the-money put is worth about $Ke^{-rT} - S$ and *falls* with $T$. Numerically, with $S = 50$, $K = 100$, $r = 10\%$, $\sigma = 20\%$, the European put is worth $47.5$ at $T = 0.25$, $40.5$ at $T = 1$, and $16.0$ at $T = 5$. For a European call on a stock paying large dividends before expiry, a longer maturity means more dividends are paid to shareholders rather than the call holder: with $S = 150$, $K = 100$, $r = 1\%$, $y = 8\%$, $\sigma = 20\%$ the call is worth $47.3$ at $T = 0.25$ but $39.9$ at $T = 1$. So the sign is ambiguous for European puts and for European calls on dividend-paying stocks.

*Step 4 -- Volatility $\sigma$ increases.* Both payoffs are convex in $S_T$ with a floor at zero: the holder keeps the upside of larger moves and is protected on the downside. More dispersion therefore raises both calls and puts, American or European. (The book's Table 6.1 lists this as an increase for every option type.)

*Step 5 -- Risk-free rate $r$ increases.* Two effects point the same way. The present value of the strike $Ke^{-rT}$ falls, which helps a call (pays $K$ later, cheaper) and hurts a put (receives $K$ later, cheaper). Also the risk-neutral drift of the stock rises, pushing $S_T$ up. Calls rise, puts fall.

*Step 6 -- Dividends increase.* On the ex-dividend date the stock drops by roughly the dividend, and the option holder does not receive it. Lower expected $S_T$ means calls fall and puts rise. (For an American call, large dividends can also make early exercise just before the ex-date optimal, but the price still falls as dividends increase.)

Answer:

(a) $S$ up: calls up, puts down. (b) $K$ up: calls down, puts up. (c) $T$ up: American calls and puts up; European call on a non-dividend stock up; European puts and European calls on dividend-paying stocks are ambiguous (deep in-the-money European puts fall with $T$). (d) $\sigma$ up: all four up. (e) $r$ up: calls up, puts down. (f) Dividends up: calls down, puts up.

Intuition

Almost every direction follows from one of two facts: an option is a bet on the terminal price relative to the strike, and its value is the present value of a convex payoff. Higher $S$, lower $K$, lower present value of the strike, or a higher risk-neutral drift all help a call and hurt a put; more uncertainty helps both because a convex payoff loves dispersion. The one genuinely subtle input is time: an American holder gets strictly more choices with more time, but a European holder is locked in, so a deep in-the-money put (or a call that misses big dividends) can lose value as maturity lengthens. On a trading desk these signs are the first sanity check on any Greek report, and the European time-to-maturity exception is exactly why American puts carry an early exercise premium.

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